def count_leading_zeros(num):
# Count leading zeros in a number
str_num = str(num)
count = 0
for digit in str_num:
if digit == ‘0’:
count += 1
else:
break
return count

def solve(n, tiles):
# Create DP array to store minimum leading zeros
dp = [[float(‘inf’)] * n for _ in range(n)]
# Create array to store products
products = [[1] * n for _ in range(n)]

# Initialize first cell
dp[0][0] = count_leading_zeros(tiles[0][0])
products[0][0] = tiles[0][0]

# Fill first row
for j in range(1, n):
products[0][j] = products[0][j-1] * tiles[0][j]
dp[0][j] = count_leading_zeros(products[0][j])

# Fill first column
for i in range(1, n):
products[i][0] = products[i-1][0] * tiles[i][0]
dp[i][0] = count_leading_zeros(products[i][0])

# Fill rest of the DP table
for i in range(1, n):
for j in range(1, n):
# Calculate product from top
top_product = products[i-1][j] * tiles[i][j]
top_zeros = count_leading_zeros(top_product)

# Calculate product from left
left_product = products[i][j-1] * tiles[i][j]
left_zeros = count_leading_zeros(left_product)

# Choose minimum leading zeros path
if top_zeros <= left_zeros:
dp[i][j] = top_zeros
products[i][j] = top_product
else:
dp[i][j] = left_zeros
products[i][j] = left_product

return dp[n-1][n-1]